News : Tour de France 2019 – Powerranking: Who will win the Tour?


News :

Tour de France 2019 - Powerranking: Who will win the Tour?


Before talking about the top favorites for this year's Tour de France, first of all you have to talk about the names that will not be used in the 106th Tour de France. For both the four-time Tour winner and last year's third Chris Froome (Ineos) and last year's second Tom Dumoulin (Sunweb) are injured.

At first glance, it makes the race for the overall victory in France more open. But even without Froome the team Ineos (formerly Sky) has the top two favorites in their own ranks. The team could thus bring the seventh victory in the past eight years.

SPIEGEL ONLINE expert Eike Hagen Hoppmann has evaluated and sorted the presumed best riders before the start of the tour. Included in the rating are the past season performances, the performance at the Tour de France in recent years, the strength of the team and how well the track suits the skills of the drivers.

A trio as a victim of double burden

Vincenzo Nibali (Bahrain Merida), Mikel Landa (Movistar) and Simon Yates (Mitchelton-Scott) are not in the top ten. Normally, the trio is among the best in the world. All three drove in May already the Giro d'Italia. The experience of recent years shows that the load with two large round trips is large within a few weeks. Other riders, who have focused only on the Tour of France in preparation, should be fresher to the start. However, you can not copy the three. You could possibly go for a podium finish. But it is also possible that they give away the overall standings early and instead focus on stage victories or the mountain jersey.

Emanuel Buchmann (Bora-hansgrohe) did not make it into the top ten riders. Although the 26-year-old drives a strong season and landed in the Tour dress rehearsal Dauphine in third place. But in the big three-week round trips, he has not been able to keep his form as consistent at a high level as he has done in a one-week race.

Here's the rankings from tenth to number one:

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